約瑟夫環(huán)是一個(gè)數(shù)學(xué)的應(yīng)用問(wèn)題：已知n個(gè)人（以編號(hào)1，2，3...n分別表示）圍坐在一張圓桌周?chē)�。從編�?hào)為k的人開(kāi)始報(bào)數(shù)，數(shù)到m的那個(gè)人出列；他的下一個(gè)人又從1開(kāi)始報(bào)數(shù)，數(shù)到m的那個(gè)人又出列；依此規(guī)律重復(fù)下去，直到圓桌周?chē)�的人全部出列�?

2B求解:

    private void myJosf(int teamLength, int baoshu) {  
        int[] team = new int[teamLength];  
      
        for (int n = 1; n < teamLength + 1; n++) {  
            team[n - 1] = n;  
        }  
      
        int index = 0;  
      
        for (int n = 0; n < teamLength; n++) {  
            for (int k = 0; k < baoshu;) {  
                if (index > teamLength - 1) {  
                    index = 0;  
                }  
      
                if (team[index] > 0) {  
                    if ((k + 1) % baoshu == 0) {  
                        System.out.println(index + 1);  
                        team[index] = 0;  
                    }  
                    k++;  
                }  
                index++;  
            }  
        }  
      
    }  

文藝求解：

    public void josephCircle(int n, int k) {  
            int flag = 0;  
            boolean[] kick = new boolean[n];  
            // set kick flag to False;  
            for (int i = 0; i < n - 1; i++) {  
                kick[flag] = false;  
            }  
      
            int counter = 0;  
            int accumulate = 0;  
            while (true) {  
                if (!kick[flag]) {  
                    accumulate++;  
                    if (counter == n - 1) {  
                        System.out.println("kick last person====" + (flag + 1));  
                        break;  
                    }  
                    if (accumulate == k) {  
                        kick[flag] = true;  
                        System.out.println("kick person====" + (flag + 1));  
                        accumulate = 0;  
                        counter++;  
                    }  
                }  
                flag = (flag + 1) % n;  
            }  
      
        }  

標(biāo)簽：

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